1、1111解：解：f=9375MHzf=9375MHz3.23.1251cfcml??????此傳輸線為長線此傳輸線為長線1212解：解：f=150kHzf=150kHz420000.5101cfml?????????此傳輸線為短線此傳輸線為短線1313答：答：當(dāng)頻率很高，傳輸線的長度與所傳電磁波的波長相當(dāng)時，低頻時忽略當(dāng)頻率很高，傳輸線的長度與所傳電磁波的波長相當(dāng)時，低頻時忽略的各種現(xiàn)象與效應(yīng)，通過沿導(dǎo)體線分布在每一點(diǎn)的損耗電阻，電感，

2、的各種現(xiàn)象與效應(yīng)，通過沿導(dǎo)體線分布在每一點(diǎn)的損耗電阻，電感，電容和漏電導(dǎo)表現(xiàn)出來，影響傳輸線上每一點(diǎn)的電磁波傳播，故稱其電容和漏電導(dǎo)表現(xiàn)出來，影響傳輸線上每一點(diǎn)的電磁波傳播，故稱其為分布參數(shù)。用為分布參數(shù)。用表示，分別稱其為傳輸線單位長度的分布表示，分別稱其為傳輸線單位長度的分布1111RLCG電阻，分布電感，分布電容和分布電導(dǎo)。電阻，分布電感，分布電容和分布電導(dǎo)。1414解：解：特性阻抗特性阻抗901012101.66510500.6

3、6610LLZCC?????????f=50Hzf=50HzX1=ωL=ωL1=2π5016.6510=2π5016.651099Ωcm=5.2310Ωcm=5.231066ΩcmΩcmB1=ωC=ωC1=2π500.6661010=2π500.66610101212=2.0910=2.091099ScmScm1515解：解：∵??22jzjzirUzUeUe????????????2201jzjzirIzUeUeZ????????將代

4、入代入2223320242irUVUVz???????????33223420220218jjzUeejjjV???????????????3412020.11200zIjjjA??????????????3418cos2jtezuztRUzetV???????????????????????????340.11cos2jteziztRIzetA?????????????????????1616解：解：∵Z∵ZL=Z=Z0∴????22

5、0jzirUzUeU???????????212321100jjzzUzeUze?????????????????611100100cos6jUzeVuzttV?????????????c)c)0173.23inZjZctgj??????d)d)02173.23inZjZctgj?????112112解：解：29.7502050100740.6215010013ojLLLZZjjeZZj????????????113113解：解：表14

6、14短路線長度短路線長度0.182λ0.182λ0.25λ0.25λ0.15λ0.15λ0.62λ0.62λ輸入阻抗輸入阻抗inZj2.2j2.2∞j1.38j1.38j0.94j0.94輸入導(dǎo)納輸入導(dǎo)納inYj0.46j0.460j0.024j0.024j1.06j1.06114114解：解：表1515開路線長度開路線長度0.1λ0.1λ0.19λ0.19λ0.37λ0.37λ0.48λ0.48λ輸入阻抗輸入阻抗inZj1.38j1.

7、38j0.4j0.4j0.94j0.94j7.9j7.9輸入導(dǎo)納輸入導(dǎo)納inYj0.73j0.73j2.5j2.5j1.06j1.06j0.13j0.13115115解：解：表1616負(fù)載阻抗負(fù)載阻抗LZ0.3j1.30.3j1.30.5j1.60.5j1.630.250.250.45j1.20.45j1.2j2.0j2.0駐波比駐波比ρ9.169.161.861.86345.75.7∞反射系數(shù)反射系數(shù)?0.80.80.30.30.50

8、.50.60.60.70.71116116解：解：表1717負(fù)載阻負(fù)載阻抗LZ0.8j0.8j0.3j1.10.3j1.1∞j1.0j1.01.01.06j36j3輸入阻輸入阻抗inZ0.488j0.610.488j0.610.23j0.850.23j0.850j1j110.13j0.0670.13j0.067輸入阻輸入阻抗inZ(Ω)(Ω)24.4j30.524.4j30.511.5j42.311.5j42.30j50j5050506